A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have the shear modulus of 1×109 N / m2 . The disk is equivalent to a solid cylinder 0.700 cm high and 4.00 cm in diameter.
Solution 38 PE
In this question, we need to find shear deformation of disk between vertebrae in the spine
Height of disk
Diameter of disk
Step 2 :
We shall find the area of the disk
Substituting values we get
Thus we have area of the cylinder as
Textbook: College Physics
Author: Paul Peter Urone, Roger Hinrichs
This textbook survival guide was created for the textbook: College Physics , edition: 1. This full solution covers the following key subjects: disk, shear, its, cylinder, equivalent. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. College Physics was written by and is associated to the ISBN: 9781938168000. Since the solution to 38PE from 5 chapter was answered, more than 1315 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 38PE from chapter: 5 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. The answer to “A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have the shear modulus of 1×109 N / m2 . The disk is equivalent to a solid cylinder 0.700 cm high and 4.00 cm in diameter.” is broken down into a number of easy to follow steps, and 49 words.