A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have the shear modulus of 1×109 N / m2 . The disk is equivalent to a solid cylinder 0.700 cm high and 4.00 cm in diameter.

Problem 38PE

Solution 38 PE

Step 1:

In this question, we need to find shear deformation of disk between vertebrae in the spine

Data given

Shear force

Shear modulus

Height of disk

Diameter of disk

Radius

Step 2 :

We shall find the area of the disk

Substituting values we get

Thus we have area of the cylinder as