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(a) What is the period of rotation of Earth in seconds?

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 4PE Chapter 6

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 4PE

(a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a radius of 6.4×106 m at its equator, what is the linear velocity at Earth’s surface?

Step-by-Step Solution:

Step 1 of 4 </p>

We have to express period of rotation of earth in seconds.after that we have to find the angular velocity of the earth and linear velocity of the earth.

Step 2 of 4</p>

The time taken by the earth to complete one rotation about its own axis is called period of rotation of earth.

The earth takes 24 hours (but exactly 23 hours 56 minutes 4 secs )to complete one rotation.

Now we have to convert  hour to sec

=24 hours(3600 s/1 hr)

=86,400 s

So the period of rotation of earth is 86,400 s.

Step 3 of 4

Chapter 6, Problem 4PE is Solved
Step 4 of 4

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

The answer to “(a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a radius of 6.4×106 m at its equator, what is the linear velocity at Earth’s surface?” is broken down into a number of easy to follow steps, and 40 words. This full solution covers the following key subjects: EARTH, velocity, period, given, its. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. This textbook survival guide was created for the textbook: College Physics , edition: 1. The full step-by-step solution to problem: 4PE from chapter: 6 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. College Physics was written by and is associated to the ISBN: 9781938168000. Since the solution to 4PE from 6 chapter was answered, more than 1244 students have viewed the full step-by-step answer.

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