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Solved: A fairground ride spins its occupants inside a
Chapter 6, Problem 10(choose chapter or problem)
A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has an 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.50 times that due to gravity?
Questions & Answers
QUESTION:
A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has an 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.50 times that due to gravity?
ANSWER:
Step 1 of 5:
A flying saucer-shaped container is used in an amusement park to have a ride. The container spins at a particular rate. The radius of the riders is given by r. The motion is considered as the horizontal circular motion. We need to find the angular velocity of the riders in revolutions per minute if they experience a centripetal acceleration (\(\mathrm{a} \text { or } \mathrm{a}_{\mathrm{C}}\)) which is 1.50 times greater than that of the acceleration due to gravity (g).
The radius of the path \(r=8.00 \mathrm{~m}\)
The centripetal acceleration experienced \(a=1.50(\mathrm{~g})\)
Where \(g=9.8 \mathrm{~ms}^{-2}\)