Problem 20PE

At takeoff, a commercial jet has a 60.0 m/s speed. Its tires have a diameter of 0.850 m.

(a) At how many rev/min are the tires rotating?

(b) What is the centripetal acceleration at the edge of the tire?

(c) With what force must a determined 1.00×10−15 kg bacterium cling to the rim?

(d) Take the ratio of this force to the bacterium’s weight.

Solution 20PE

We are required to calculate the angular velocity of the tires, centripetal acceleration, centripetal force on a bacterium and the ratio of the centripetal force on the bacterium to its weight.

Part a

Step 1 of 5

Given data,

Linear speed of the jet m/s

Diameter of its tire m

Radius m

Angular velocity

rad/s

rad/s

Now, 1 rev = 2 radians

141 radians revolutions

1 min = 60 s

1 s = 1/60 min