(a) A 22.0 kg child is riding a playground merry-go-round

College Physics by Urone | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone

Problem 23PE Chapter 6

College Physics by Urone | 1st Edition

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College Physics by Urone | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone

College Physics by Urone | 1st Edition

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Problem 23PE

(a) A 22.0 kg child is riding a playground merry-go-round that is rotating at 40.0 rev/min. What centripetal force must she exert to stay on if she is 1.25 m from its center?

(b) What centripetal force does she need to stay on an amusement park merry-go-round that rotates at 3.00 rev/min if she is 8.00 m from its center?

(c) Compare each force with her weight.

Step-by-Step Solution:

Step 1 of Step 4</p>

A) 

We have to find the centripetal force of the rotating merry-go-round from its center. Given mass of a child m=25 kg, angular acceleration and r is the radius from the center of rotating merry-go-round r=1.25m

Step 2 of Step 4</p>

=483 N is the centripetal force of the rotating merry-go-round from its center 

Step 3 of 4

Chapter 6, Problem 23PE is Solved
Step 4 of 4

Textbook: College Physics by Urone
Edition: 1st
Author: Paul Peter Urone
ISBN: 9781938168000

This full solution covers the following key subjects: Force, rev, centripetal, round, stay. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. The answer to “(a) A 22.0 kg child is riding a playground merry-go-round that is rotating at 40.0 rev/min. What centripetal force must she exert to stay on if she is 1.25 m from its center?(b) What centripetal force does she need to stay on an amusement park merry-go-round that rotates at 3.00 rev/min if she is 8.00 m from its center?(c) Compare each force with her weight.” is broken down into a number of easy to follow steps, and 65 words. This textbook survival guide was created for the textbook: College Physics by Urone, edition: 1st. College Physics by Urone was written by Sieva Kozinsky and is associated to the ISBN: 9781938168000. Since the solution to 23PE from 6 chapter was answered, more than 590 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 23PE from chapter: 6 was answered by Sieva Kozinsky, our top Physics solution expert on 07/07/17, 04:39PM.

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