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Unreasonable Results(a) Based on Kepler’s laws and

Chapter 6, Problem 49

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QUESTION:

Problem 49PE

Unreasonable Results

(a) Based on Kepler’s laws and information on the orbital characteristics of the Moon, calculate the orbital radius for an Earth satellite having a period of 1.00 h. (b) What is unreasonable about this result? (c) What is unreasonable or inconsistent about the premise of a 1.00 h orbit?

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QUESTION:

Problem 49PE

Unreasonable Results

(a) Based on Kepler’s laws and information on the orbital characteristics of the Moon, calculate the orbital radius for an Earth satellite having a period of 1.00 h. (b) What is unreasonable about this result? (c) What is unreasonable or inconsistent about the premise of a 1.00 h orbit?

ANSWER:

Solution  49 PE

The orbital radius for an Earth satellite can be calculated using the Kepler’s third law which relates the time period of the satellite to the radius of the orbit.

a.)

Step 1 of  4

The orbital characteristics of the Moon are

Time period of the moon Tm is  Tm= 27.3 days

Radius of the orbit rm is  rm= 3.84 m

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