Solution Found!
Unreasonable Results(a) Based on Kepler’s laws and
Chapter 6, Problem 49(choose chapter or problem)
Problem 49PE
Unreasonable Results
(a) Based on Kepler’s laws and information on the orbital characteristics of the Moon, calculate the orbital radius for an Earth satellite having a period of 1.00 h. (b) What is unreasonable about this result? (c) What is unreasonable or inconsistent about the premise of a 1.00 h orbit?
Questions & Answers
QUESTION:
Problem 49PE
Unreasonable Results
(a) Based on Kepler’s laws and information on the orbital characteristics of the Moon, calculate the orbital radius for an Earth satellite having a period of 1.00 h. (b) What is unreasonable about this result? (c) What is unreasonable or inconsistent about the premise of a 1.00 h orbit?
ANSWER:
Solution 49 PE
The orbital radius for an Earth satellite can be calculated using the Kepler’s third law which relates the time period of the satellite to the radius of the orbit.
a.)
Step 1 of 4
The orbital characteristics of the Moon are
Time period of the moon Tm is Tm= 27.3 days
Radius of the orbit rm is rm= 3.84 m