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Calculate the power output in watts and horsepower of a

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 46PE Chapter 7

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 46PE

Calculate the power output in watts and horsepower of a shot-putter who takes 1.20 s to accelerate the 7.27-kg shot from rest to 14.0 m/s, while raising it 0.800 m. (Do not include the power produced to accelerate his body.)

Step-by-Step Solution:

Solution 46 PE

Step 1 of 5</p>

The power output of  the shot-putter can be calculated by finding the sum of work done in raising the shot put to 0.8 m which is nothing but the gravitational potential energy of the shot put at that height (W1 ) and work done in accelerating the shot put from rest to 14.0 m/s (W2)

Step 2 of 5</p>

The gravitational potential energy PEs of the shot put  at a height h from the ground is

Where, g = acceleration due to gravity = 9.8 m/s2

             m = mass of the shot put  = 7.27 kg

             h = distance from the ground = 0.8 m

This potential energy is equal to the work done(W1) in raising the shot put.

So,      Substitute 7.27  kg for m, 9.8 m/s2 for g, 0.8 m for h    

       = ( 7.72 ) (9.8) (0.8)

 W1 = 60.52 J

Step 3 of 5</p>

The work done (W2) can be calculated using the Work - Energy Theorem which states that the net work done by the system is equal to change in the quantity ½ m v2.

Here,   m =  mass of the sprinter = 7.27  kg             v = final velocity = 14.0 m/s             vo= initial velocity = 0 m/s

Substituting 7.27 kg for m, 14.0 m/s for v, 0 m/s for vo

         =

          = ( 0.5) (7.27) (196)

    W2   = 712. 46 J

Step 4 of 5</p>

The power output (P) of the shot putter is then by definition the amount of total work done in the given time.

  Here, t = 1.20 s

Now, the total work done by the shot putter  is,

 

                   

                     = 772.98 J

Now,

              = 

            = 644.15 W

Step 5 of 5</p>

Conversion of power in watts to horsepower .

1 horsepower = 746 W

So,  644.15 W = 644.15 W

                        = 0.86 horsepower

Therefore, the power output  of the shot putter is 644.15 in watts or 0.86  horsepower.

                           

Step 2 of 2

Chapter 7, Problem 46PE is Solved
Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

This textbook survival guide was created for the textbook: College Physics , edition: 1. The full step-by-step solution to problem: 46PE from chapter: 7 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This full solution covers the following key subjects: accelerate, shot, power, produced, include. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. Since the solution to 46PE from 7 chapter was answered, more than 5044 students have viewed the full step-by-step answer. The answer to “Calculate the power output in watts and horsepower of a shot-putter who takes 1.20 s to accelerate the 7.27-kg shot from rest to 14.0 m/s, while raising it 0.800 m. (Do not include the power produced to accelerate his body.)” is broken down into a number of easy to follow steps, and 40 words. College Physics was written by and is associated to the ISBN: 9781938168000.

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