×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide

Solved: Construct Your Own an artillery projectile

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 64PE Chapter 8

College Physics | 1st Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

4 5 0 309 Reviews
27
2
Problem 64PE

Construct Your Own Problem

Consider an artillery projectile striking armor plating. Construct a problem in which you find the force exerted by the projectile on the plate. Among the things to be considered are the mass and speed of the projectile and the distance over which its speed is reduced. Your instructor may also wish for you to consider the relative merits of depleted uranium versus lead projectiles based on the greater density of uranium.

Step-by-Step Solution:

Solution 64 PE

Step 1 of 6</p>

An artillery projectile made of depleted uranium of mass 0.5 kg strikes an armor plating at a distance of 12.0 cm The speed of the  projectile is 14.00 m/s and the angle of projection is 35o. Calculate the force exerted by the projectile on the plate.

Step 2 of 6</p>

The force exerted by the projectile on the plate can be calculated using Newton’s second law of motion.

Here, m = mass of the artillery = 0.5 kg

          a = acceleration of the projectile in m s2

The acceleration of the projectile can be found using equation of kinematics.

Where, v = vxvf

              vffinal velocity in m/s = 0

            vx= horizontal velocity in m/s

             t = t - to

              toinitial time in s

            t = time of flight in s

             g = acceleration due to gravity in m/s2

Step 3 of 6</p>

The  horizontal velocity vx is given by

Here, v = speed of the projectile in m/s2         

         projectile angle

Substitute 14.00 m/s2 for v and 35o for

   

       = 14 (0.8192)

 = 11.47 m/s

Step 4 of 6

Chapter 8, Problem 64PE is Solved
Step 5 of 6

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Solved: Construct Your Own an artillery projectile

×
Log in to StudySoup
Get Full Access to Physics - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Physics - Textbook Survival Guide
×
Reset your password