A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force exerted on a 0.0300-kg bullet to accelerate it to a speed of 600 m/s in a time of 2.00 ms (milliseconds)?

Solution 7PE

Step 1 of 3

The average force exerted on the bullet can be calculated using Newton’s second law which relates the mass and acceleration of the bullet with the force exerted .

where, m = mass of the bullet = 0.03 kg

a = acceleration of the bullet in m/s2.

Step 2 of 3

The acceleration of the bullet can be calculated by taking the ratio of change in the velocity to change in the time.

=

where, v = v vo

t = t to

v and voare initial and final velocity respectively.

t and to are initial and final velocity respectively.

Here, v = 600 m/s and vo= 0 m/s

t = 2.00 ms = 210-3 s and to= 0 s

So,=

=

=

= 300000 ms-2

a = 3105 ms-2