Suppose a clay model of a koala bear has a mass of 0.200 kg and slides on ice at a speed of 0.750 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.350 kg. Both being soft clay, they naturally stick together. What is their final velocity?

Solution 24PE

Step 1 of 5</p>

The first clay model of a koala bear having the mass moving with velocity towards another clay sliding on ice and the second clay with mass of is at rest . After the collision, the two clays are coupled together by being bumped into one another. Here we need to calculate the final velocity of that coupled clay .

Given data,

Mass of first clay,

Velocity of first clay,

Mass of second clay,

Velocity of second clay,

To find,

The final velocity of that coupled clay,

Step 2 of 5</p>

We can calculate the final velocity of the coupled clay after collision using the law of conservation of linear momentum. Which states that, the total linear momentum of the system remains constant in other words, total linear momentum before collision must be equal to total linear momentum after collision.

That is, ………...1

Where and are the total linear momentum before collision and total linear momentum after collision.

Step 3 of 5</p>To calculate the total linear momentum before collision,

Before collision,

Before collision the total linear momentum is equal to the sum of individual linear momentum of two clay models and is given by,

………...2