Professional Application Two manned satellites approaching one another, at a relative speed of 0.250 m/s, intending to dock. The first has a mass of 4.00×103 kg , and the second a mass of 7.50×103 kg . (a) Calculate the final velocity (after docking) by using the frame of reference in which the first satellite was originally at rest. (b) What is the loss of kinetic energy in this inelastic collision? (c) Repeat both parts by using the frame of reference in which the second satellite was originally at rest. Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.
Step 1 of Step 5</p>
A two man-made satellite is approaching in one direction at the relative speed in the same direction one other intending to dock, these two satellites have masses. We have to find the final velocity of the first satellite which is at rest.
Given mass m1=4000 kg and m2=7500 kg, velocity V1=0 and V2=0.250m/s
Step 2 of Step 5</p>
By velocity equation we have
=0.1630 m/s is the final velocity.
Step 3 of Step 5</p>
We have to final the kinetic energy loss. Hence we have to consider both final and initial of K.E
The loss of K.E=K.Ef -K.Ei
0.25J is the K.E loss from the inelastic collision.