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Solved: Derive the equation for the vertical acceleration

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 57PE Chapter 8

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 57PE

Derive the equation for the vertical acceleration of a rocket.

Step-by-Step Solution:

Solution 57 PE

Step 1 of 3:

In this question, we need to derive an equation for vertical acceleration of rocket

Step 2 of 3:

We shall consider small mass  on which a certain force is acted upon

The acceleration on mass be given by

Thus we get force as

                                

                                 ------------------------(1)

Now we need to accelerate this mass in small time interval and at speed

Here the velocity is given by

                        

                                

Rearranging to obtain

                

                                -----------------------------(2)

                                

Hence using equation (2) we substitute for acceleration  in equation (1)

We get

                                ---------------------------(3)

Step 3 of 3

Chapter 8, Problem 57PE is Solved
Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

The answer to “Derive the equation for the vertical acceleration of a rocket.” is broken down into a number of easy to follow steps, and 10 words. The full step-by-step solution to problem: 57PE from chapter: 8 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This textbook survival guide was created for the textbook: College Physics , edition: 1. This full solution covers the following key subjects: acceleration, derive, equation, rocket, vertical. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. College Physics was written by and is associated to the ISBN: 9781938168000. Since the solution to 57PE from 8 chapter was answered, more than 239 students have viewed the full step-by-step answer.

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