Solution Found!
Solved: Repeat the seesaw problem in Example 9.1 with the
Chapter 9, Problem 5(choose chapter or problem)
Repeat the seesaw problem in Example \(9.1\) with the center of mass of the seesaw \(0.160 \mathrm{~m}\) to the left of the pivot (on the side of the lighter child) and assuming a mass of \(12.0 \mathrm{~kg}\) for the seesaw. The other data given in the example remain unchanged. Explicitly show how you follow the steps in the Problem-Solving Strategy for static equilibrium.
Equation Transcription:
Text Transcription:
9.1
0.160 m
12.0 kg
Questions & Answers
QUESTION:
Repeat the seesaw problem in Example \(9.1\) with the center of mass of the seesaw \(0.160 \mathrm{~m}\) to the left of the pivot (on the side of the lighter child) and assuming a mass of \(12.0 \mathrm{~kg}\) for the seesaw. The other data given in the example remain unchanged. Explicitly show how you follow the steps in the Problem-Solving Strategy for static equilibrium.
Equation Transcription:
Text Transcription:
9.1
0.160 m
12.0 kg
ANSWER:
Solution 5PE:
Step 1 of 5:-
Here our goal is to solve example 9.1, where,
The mass of one child is, ,
The mass of another child is, .
The 1st child is at a certain distance from the centre of mass, which is, .
By the definition of centre of mass for a two body system,