(a) Calculate the magnitude and direction of the force on each foot of the horse in Figure 9.31 (two are on the ground), assuming the center of mass of the horse is midway between the feet. The total mass of the horse and rider is 500kg. (b) What is the minimum coefficient of friction between the hooves and ground? Note that the force exerted by the wall is horizontal.
Step 1 of 6:
A horse is standing on the ground and two forces acting on each foot of the horse. The center of gravity of the horse is located in the middle of the feet. We are going to find the value and the direction of the force.
The mass of the horse with the rider
The acceleration due to gravity
The distance between the ground and center of gravity
The distance between the ground and the point where frictional force is felt
The distance between the center of gravity and the middle of the feet
There force on each foot is the resultant force of the half of the frictional force acting on the wall and the half of the weight of the horse with the rider.
Step 2 of 6:
The frictional force acting between the wall and the horse is not given directly. The horse standing beside the wall applies a force on the wall and the wall produces the reaction. And in the vertical direction, the weight and the normal forces are acting. The net force and the net torque acting are zero since the system is in equilibrium.
The net horizontal forces in equilibrium
The net vertical forces in equilibrium
The net torque
Substituting the values of N and f and solving for FW
Substituting the known quantities
The force on the wall or the frictional force is 1429.17 N.
Step 3 of 6:
The weight of the horse