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Solved: To get up on the roof, a person (mass 70.0 kg)

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 17PE Chapter 9

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 17PE

To get up on the roof, a person (mass 70.0 kg) places a 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. The ladder rests against a plastic rain gutter, which we can assume to be frictionless. The center of mass of the ladder is 2 m from the bottom. The person is standing 3 m from the bottom. What are the magnitudes of the forces on the ladder at the top and bottom?

Step-by-Step Solution:

Solution 17 PE

Step 1 of 5</p>

The magnitude of forces on the acting on the top and bottom of the ladder can be found by writing down the equation for net torque acting on the top of the ladder and net vertical  force acting on the bottom of the ladder and applying the conditions of equilibrium to it.

Step 2 of 5</p>

The free body  diagram is as shown in the figure below.

Let the length of the ladder be , the distance between the base of the ladder and the house be ,  distance of the person from the base of  the bottom be .

The center of  mass of the ladder is at a distance of 2 m from the bottom of the ladder. So, the weight  of the ladder is acting downwards at that point. The weight  of the person is acting at distance of 3 m from the base of the ladder downwards.

Now, the force acting at the top and bottom of the ladder are the  normal reaction acting at the top and bottom of the ladder are and  respectively. The friction force exerted by the ground on the ladder is . The ladder makes an angle with the ground.

.

Step 3 of 5</p>

The angle is given by  

 

Where,  = distance from the house to bottom of the ladder in m,

              = length of the ladder in m

Substituting 2 m for  and 6 m for

 

             =

= 70.53o

Step 4 of 5

Chapter 9, Problem 17PE is Solved
Step 5 of 5

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

This textbook survival guide was created for the textbook: College Physics , edition: 1. The full step-by-step solution to problem: 17PE from chapter: 9 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. College Physics was written by and is associated to the ISBN: 9781938168000. The answer to “To get up on the roof, a person (mass 70.0 kg) places a 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. The ladder rests against a plastic rain gutter, which we can assume to be frictionless. The center of mass of the ladder is 2 m from the bottom. The person is standing 3 m from the bottom. What are the magnitudes of the forces on the ladder at the top and bottom?” is broken down into a number of easy to follow steps, and 89 words. This full solution covers the following key subjects: ladder, mass, bottom, against, house. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. Since the solution to 17PE from 9 chapter was answered, more than 971 students have viewed the full step-by-step answer.

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Solved: To get up on the roof, a person (mass 70.0 kg)

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