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During a very quick stop, a car decelerates at 7.00

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 8PE Chapter 10

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 8PE

During a very quick stop, a car decelerates at 7.00 m/s2.

(a) What is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement?

(b) How many revolutions do the tires make before coming to rest, given their initial angular velocity is 95.0 rad/s ?

(c) How long does the car take to stop completely?

(d) What distance does the car travel in this time?

(e) What was the car’s initial velocity?

(f) Do the values obtained seem reasonable, considering that this stop happens very quickly?

Step-by-Step Solution:

Solution 8PE

From the data given, we are required to calculate various quantities considering the equations of rotational motion.

Part a

Step 1 of 6</p>

The rate of deceleration of the car is  m/s2

The radius of the tire is  m

Therefore, the angular acceleration

 rad/s2

rad/s2

Therefore, the angular acceleration of the tire is 25.0 rad/s2.

Part b

Step 2 of 6</p>

Since the tires come to rest, hence final angular velocity is .

Initial angular velocity rad/s

Therefore, the time taken

s

s

The angular displacement of the tires at 3.80 s is,

rad

rad

Now, rev = rad

So, 180.5 rad rev

 rad rev

                 rev

The tires would make approximately 29 revolutions before coming to rest.

Part c

Step 3 of 6</p>

Since the tires come to rest, hence final angular velocity is .

Initial angular velocity rad/s

Therefore, the time taken

s

s

Therefore, the car would take 3.80 s to stop completely.

Part d

Step 4 of 6

Chapter 10, Problem 8PE is Solved
Step 5 of 6

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

The answer to “During a very quick stop, a car decelerates at 7.00 m/s2.(a) What is the angular acceleration of its 0.280-m-radius tires, assuming they do not slip on the pavement?(b) How many revolutions do the tires make before coming to rest, given their initial angular velocity is 95.0 rad/s ?(c) How long does the car take to stop completely?(d) What distance does the car travel in this time?(e) What was the car’s initial velocity?(f) Do the values obtained seem reasonable, considering that this stop happens very quickly?” is broken down into a number of easy to follow steps, and 85 words. College Physics was written by and is associated to the ISBN: 9781938168000. This textbook survival guide was created for the textbook: College Physics , edition: 1. The full step-by-step solution to problem: 8PE from chapter: 10 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. Since the solution to 8PE from 10 chapter was answered, more than 4265 students have viewed the full step-by-step answer. This full solution covers the following key subjects: Car, stop, tires, velocity, Very. This expansive textbook survival guide covers 34 chapters, and 3125 solutions.

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