Problem 15PE

Consider the 12.0 kg motorcycle wheel shown in Figure 10.38. Assume it to be approximately an annular ring with an inner radius of 0.280 m and an outer radius of 0.330 m. The motorcycle is on its center stand, so that the wheel can spin freely. (a) If the drive chain exerts a force of 2200 N at a radius of 5.00 cm, what is the angular acceleration of the wheel? (b) What is the tangential acceleration of a point on the outer edge of the tire? (c) How long, starting from rest, does it take to reach an angular velocity of 80.0 rad/s?

Solution

Step 1 of 5

Consider a motorcycle is in center stand and the wheel can spin freely whose inner radius is and outer radius .

a) We need to find out the angular acceleration of the wheel if the chain exert a force and at radius .

The angular acceleration is nothing but the ratio of the torque generated when the chain exert a force and the moment of inertia of the wheel.

.................(1)