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Solved: Starting with the formula for the moment of
Chapter 10, Problem 18(choose chapter or problem)
Starting with the formula for the moment of inertia of a rod rotated around an axis through one end perpendicular to its length \(\left(I=M \ell^{2} / 3\right)\), prove that the moment of inertia of a rod rotated about an axis through its center perpendicular to its length is \(I=M \ell^{2} / 12\). You will find the graphics in Figure \(10.12\) useful in visualizing these rotations.
Equation Transcription:
Text Transcription:
(I = M ell^2 / 3)
I = M ell^2 / 12
10.12
Questions & Answers
QUESTION:
Starting with the formula for the moment of inertia of a rod rotated around an axis through one end perpendicular to its length \(\left(I=M \ell^{2} / 3\right)\), prove that the moment of inertia of a rod rotated about an axis through its center perpendicular to its length is \(I=M \ell^{2} / 12\). You will find the graphics in Figure \(10.12\) useful in visualizing these rotations.
Equation Transcription:
Text Transcription:
(I = M ell^2 / 3)
I = M ell^2 / 12
10.12
ANSWER:Solution to 18PE
Sep 1 of 2
We need to prove that the moment of inertia of a rod rotated about an axis through center and perpendicular to length is
