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In the text, it was shown that N / V = 2.68×1025 m ?3 for

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 27PE Chapter 13

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 27PE

In the text, it was shown that N / V = 2.68×1025 m −3 for gas at STP. (a) Show that this quantity is equivalent to N / V = 2.68×1019 cm−3 , as stated. (b) About how many atoms are there in one μm3 (a cubic micrometer) at STP? (c) What does your answer to part (b) imply about the separation of atoms and molecules?

Step-by-Step Solution:
Step 1 of 3

Solution 27PE

A.

= ( 2.68 x 1025/cm3) ()

    = 2.68 x 1019/cm3

Hence,  is...

Step 2 of 3

Chapter 13, Problem 27PE is Solved
Step 3 of 3

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

Since the solution to 27PE from 13 chapter was answered, more than 266 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 27PE from chapter: 13 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This textbook survival guide was created for the textbook: College Physics , edition: 1. This full solution covers the following key subjects: atoms, STP, part, equivalent, gas. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. The answer to “In the text, it was shown that N / V = 2.68×1025 m ?3 for gas at STP. (a) Show that this quantity is equivalent to N / V = 2.68×1019 cm?3 , as stated. (b) About how many atoms are there in one ?m3 (a cubic micrometer) at STP? (c) What does your answer to part (b) imply about the separation of atoms and molecules?” is broken down into a number of easy to follow steps, and 66 words. College Physics was written by and is associated to the ISBN: 9781938168000.

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