In the text, it was shown that N / V = 2.68×1025 m −3 for gas at STP. (a) Show that this quantity is equivalent to N / V = 2.68×1019 cm−3 , as stated. (b) About how many atoms are there in one μm3 (a cubic micrometer) at STP? (c) What does your answer to part (b) imply about the separation of atoms and molecules?
Step 1 of 3
= ( 2.68 x 1025/cm3) ()
= 2.68 x 1019/cm3
Hence, is equivalent to 2.68 x 1019/cm3 at STP.
Therefore, approximately 2.68 x 107 atoms exist per 3
Therefore, the average separation between the atoms is approx 3.34 nm
Textbook: College Physics
Author: Paul Peter Urone, Roger Hinrichs
Since the solution to 27PE from 13 chapter was answered, more than 319 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 27PE from chapter: 13 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This textbook survival guide was created for the textbook: College Physics , edition: 1. This full solution covers the following key subjects: atoms, STP, part, equivalent, gas. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. The answer to “In the text, it was shown that N / V = 2.68×1025 m ?3 for gas at STP. (a) Show that this quantity is equivalent to N / V = 2.68×1019 cm?3 , as stated. (b) About how many atoms are there in one ?m3 (a cubic micrometer) at STP? (c) What does your answer to part (b) imply about the separation of atoms and molecules?” is broken down into a number of easy to follow steps, and 66 words. College Physics was written by and is associated to the ISBN: 9781938168000.