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Get Full Access to Elementary Differential Equations And Boundary Value Problems - 10 Edition - Chapter 10.5 - Problem 20
Get Full Access to Elementary Differential Equations And Boundary Value Problems - 10 Edition - Chapter 10.5 - Problem 20

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# In solving differential equations, the computations can

ISBN: 9780470458310 168

## Solution for problem 20 Chapter 10.5

Elementary Differential Equations and Boundary Value Problems | 10th Edition

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Problem 20

In solving differential equations, the computations can almost always be simplified by theuse of dimensionless variables.(a) Show that if the dimensionless variable = x/L is introduced, the heat conductionequation becomes2u2 = L22ut, 0 << 1, t > 0.(b) Since L2/2 has the units of time, it is convenient to use this quantity to define a dimensionlesstime variable = (2/L2)t. Then show that the heat conduction equationreduces to2u2 = u , 0 << 1, > 0.

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L21 - 6 ex. Aditbedofitbyugi through an inverted cone-shaped ﬁlter. The height of the cone is 20 inches and the diameter across the top is 16 inches. If the liquid is ﬂowing out at 2 cubic in/min, how fast is the depth of the liquid changing when it is 12 inches deep

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##### ISBN: 9780470458310

The full step-by-step solution to problem: 20 from chapter: 10.5 was answered by , our top Math solution expert on 12/23/17, 04:36PM. Elementary Differential Equations and Boundary Value Problems was written by and is associated to the ISBN: 9780470458310. Since the solution to 20 from 10.5 chapter was answered, more than 243 students have viewed the full step-by-step answer. This full solution covers the following key subjects: . This expansive textbook survival guide covers 76 chapters, and 2039 solutions. This textbook survival guide was created for the textbook: Elementary Differential Equations and Boundary Value Problems, edition: 10. The answer to “In solving differential equations, the computations can almost always be simplified by theuse of dimensionless variables.(a) Show that if the dimensionless variable = x/L is introduced, the heat conductionequation becomes2u2 = L22ut, 0 << 1, t > 0.(b) Since L2/2 has the units of time, it is convenient to use this quantity to define a dimensionlesstime variable = (2/L2)t. Then show that the heat conduction equationreduces to2u2 = u , 0 << 1, > 0.” is broken down into a number of easy to follow steps, and 75 words.

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