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A 4-ton air conditioner removes 5.06 × 107 J (48,000

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 45PE Chapter 15

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 45PE

Problem 45PE

A 4-ton air conditioner removes 5.06 × 107 J (48,000 British thermal units) from a cold environment in 1.00 h. (a) What energy input in joules is necessary to do this if the air conditioner has an energy efficiency rating ( EER ) of 12.0? (b) What is the cost of doing this if the work costs 10.0 cents per 3.60×106 J (one kilowatt-hour)? (c) Discuss whether this cost seems realistic. Note that the energy efficiency rating ( EER ) of an air conditioner or refrigerator is defined to be the number of British thermal units of heat transfer from a cold environment per hour divided by the watts of power input.

Step-by-Step Solution:
Step 1 of 3

Solution  45PE

  1. The required energy  1.44x103 J
  2. The cost of doing work is  40o C
  3. From the above result one can conclude that the cost of doing work is reasonable. This is because, the result says that if the air conditioner runs for the entire day continuously, it would cost about $9.59.

Step 2 of 3

Chapter 15, Problem 45PE is Solved
Step 3 of 3

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

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A 4-ton air conditioner removes 5.06 × 107 J (48,000