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Physics / University Physics 13 / Chapter 21 / Problem 36E

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

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(a) Calculate the magnitude and direction (relative to the

Chapter 21, Problem 36E

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QUESTION:

(a) Calculate the magnitude and direction (relative to the +x-axis) of the electric field in Example 21.6.

(b) A point charge is placed at point P in Fig. 21.19. Find the magnitude and direction of (i) the force that the -8.0-nC charge at the origin exerts on this charge and (ii) the force that this charge exerts on the -8.0-nC charge at the origin.

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QUESTION:

(a) Calculate the magnitude and direction (relative to the +x-axis) of the electric field in Example 21.6.

(b) A point charge is placed at point P in Fig. 21.19. Find the magnitude and direction of (i) the force that the -8.0-nC charge at the origin exerts on this charge and (ii) the force that this charge exerts on the -8.0-nC charge at the origin.

ANSWER:

Solution 36E We electrostatic force between two charges is given by, 9 q 1 2 F = 9.0 × 10 × r2 …..(1), where q and1q are th2 two charges and r is the separation between them. From the given question, we have the electric field vector. E = ( 11 N/C) i + (14 N/C) j | | 2 2 The magnitude of the electric field vector is| |= ( 11) + (14) N/C E = 17.80 N/C | | Let be the angle made by the electric field vector with the x-axis. tan = E Y = 14 = 1.27 E X 11 = tan ( 1.27) = 52 0

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