(a) Calculate the magnitude and direction (relative to the

Solution 36E We electrostatic force between two charges is given by, 9 q 1 2 F = 9.0 × 10 × r2 …..(1), where q and1q are th2 two charges and r is the separation between them. From the given question, we have the electric field vector. E = ( 11 N/C) i + (14 N/C) j | | 2 2 The magnitude of the electric field vector is| |= ( 11) + (14) N/C E = 17.80 N/C | | Let be the angle made by the electric field vector with the x-axis. tan = E Y = 14 = 1.27 E X 11 = tan ( 1.27) = 52 0 0 0 0 Therefore, the electric field vector makes an angle of (180 52 ) = 128 with the positive x-axis. Figure 1 Figure 2 Since both charges are negative hence the electrostatic force on one due to the other will be repulsive. The directions...