(a) Calculate the magnitude and direction (relative to the
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Solution 36E We electrostatic force between two charges is given by, 9 q 1 2 F = 9.0 × 10 × r2 …..(1), where q and1q are th2 two charges and r is the separation between them. From the given question, we have the electric field vector. E = ( 11 N/C) i + (14 N/C) j | | 2 2 The magnitude of the electric field vector is| |= ( 11) + (14) N/C E = 17.80 N/C | | Let be the angle made by the electric field vector with the x-axis. tan = E Y = 14 = 1.27 E X 11 = tan ( 1.27) = 52 0 0 0 0 Therefore, the electric field vector makes an angle of (180 52 ) = 128 with the positive x-axis. Figure 1 Figure 2 Since both charges are negative hence the electrostatic force on one due to the other will be repulsive. The directions...
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
The full step-by-step solution to problem: 36E from chapter: 21 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. Since the solution to 36E from 21 chapter was answered, more than 232 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “(a) Calculate the magnitude and direction (relative to the” is broken down into a number of easy to follow steps, and 9 words. University Physics was written by and is associated to the ISBN: 9780321675460. This full solution covers the following key subjects: calculate, direction, magnitude, relative. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.