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Positive Charge +Q is distributed uniformly along the

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 95P Chapter 21

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 95P

Positive Charge +Q is distributed uniformly along the +x-axis from x = 0 to x = a. Negative charge ?Q is distributed uniformly along the ?x-axis from x = 0 to x = ?a. (a) A positive point charge q lies on the positive y-axis, a distance y form the origin. Find the force (magnitude and direction) that the positive negative charge distributions together exert on q. Show that this force is proportional to y?3 for y ? a. (b) Suppose instead that the positive point charge q lies on the positive x-axis, a distance x > a from the orgin. Find the force (magnitude and direction) that the charge distribution exerts on q. Show that this force is proportional to x?3 for x ? a.

Step-by-Step Solution:

Solution 95P Introduction We have to calculate the total force on the charge q due to the charge distribution when the charge q is on the y axis and on the x axis. Step 1: Because of the symmetry of the problem, the y component of the force for the negative and positive part will be canceled out and only the x component will survive. Hnce we will calculate the x component for each distribution and then add them. Also the because of the same symmetry the x component of the force will be same for both. Hence we will calculate the x component once then we can just multiply by two. To calculate the force, let us consider an elementary length of charge dx at a distance x fro the origin, and then we will calculate the force due to that elementary length and then we will integrate over the whole range, that is from a to 0. The linear charge density of the charge distribution of the negative side is Hence the charge of the elementary length is Hence the force due to the part to the point is Where is the distance of the charge from the elementary length. And . Hence the component of the force is Now putting all the values we have Hence the total x component of the force is So the total component of the force due to the both side of the charge distribution will be And the direction of the force is towards the negative axis. Step 2: If we take then we have Hence it is proved that at very large value of the force varies as .

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Chapter 21, Problem 95P is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

The answer to “Positive Charge +Q is distributed uniformly along the +x-axis from x = 0 to x = a. Negative charge ?Q is distributed uniformly along the ?x-axis from x = 0 to x = ?a. (a) A positive point charge q lies on the positive y-axis, a distance y form the origin. Find the force (magnitude and direction) that the positive negative charge distributions together exert on q. Show that this force is proportional to y?3 for y ? a. (b) Suppose instead that the positive point charge q lies on the positive x-axis, a distance x > a from the orgin. Find the force (magnitude and direction) that the charge distribution exerts on q. Show that this force is proportional to x?3 for x ? a.” is broken down into a number of easy to follow steps, and 126 words. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 95P from 21 chapter was answered, more than 306 students have viewed the full step-by-step answer. This full solution covers the following key subjects: Positive, Charge, Force, axis, proportional. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The full step-by-step solution to problem: 95P from chapter: 21 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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