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A flat sheet of paper of area 0.250 m2 is oriented so that

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 1E Chapter 22

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 1E

A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60o to a uniform electric field of magnitude 14 N/C. (a) Find the magnitude of the electric flux through the sheet. (b) Does the answer to part (a) depend on the shape of the sheet? Why or why not? (c) For what angle ? between the normal to the sheet and the electric field is the magnitude of the flux through the sheet (i) largest and (ii) smallest? Explain your answers.

Step-by-Step Solution:

Solution 1E Step 1 of 3: The magnitude of the electric flux through the sheet is given byE =E cos dA Where is the angle between the normal to the sheet n and the electric field E. Now, E and cosare constant over the surface so, = E cos dA E = E cosA = (14) (cos60 )(0.250) 2 = 1.8 N m / C

Step 2 of 3

Chapter 22, Problem 1E is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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A flat sheet of paper of area 0.250 m2 is oriented so that