A flat sheet of paper of area 0.250 m2 is oriented so that the normal to the sheet is at an angle of 60o to a uniform electric field of magnitude 14 N/C. (a) Find the magnitude of the electric flux through the sheet. (b) Does the answer to part (a) depend on the shape of the sheet? Why or why not? (c) For what angle ? between the normal to the sheet and the electric field is the magnitude of the flux through the sheet (i) largest and (ii) smallest? Explain your answers.
Solution 1E Step 1 of 3: The magnitude of the electric flux through the sheet is given byE =E cos dA Where is the angle between the normal to the sheet n and the electric field E. Now, E and cosare constant over the surface so, = E cos dA E = E cosA = (14) (cos60 )(0.250) 2 = 1.8 N m / C