A point charge of –2.00 ?C is located in the center of a spherical cavity of radius 6.50 cm inside an insulating charged solid. The charge density in the solid is ?? = 7.35 × 10–4 C/m3. Calculate the electric field inside the solid at a distance of 9.50 cm from the center of the cavity.

Solution 22E We shall have to calculate the volume of the space between the cavity and the solid. The radius of the cavity r = 6.50 cm = 6.50 × 10 2m Distance from the center of cavity at which field has to be calculated 2 d = 9.50 cm = 9.50 × 10 m 4 3 Therefore, the volume of the space V = (d3 r ) 3 V = 4 × 3.14 × [9.50 × 10 6 6.50 × 10 ] m = 2439 × 10 6m 3 3 4 3 Surface...