Two protons are released from rest when they are 0.750 nm

Step 1 of 5

The electrostatic potential energy is,

\(U = \frac{{k{q_1}{q_2}}}{r}\)

Here, \(k\) is the electrostatic constant, \({q_1}?\) and \({q_2}\)? are the magnitudes of the charges, and \(r\) is the distance between them.

The kinetic energy is given as,

\(K = \frac{1}{2}m{v^2}\)

Here, \(m\) is the mass, and \(v\) is the speed.

The conservation of energy principle states that the total energy of an isolated system is conserved that is,

\({U_i} + {K_i} = {U_f} + {K_f}\)

Here, the subscripts \(i\) stands for initial, and \(f\) stands for final.