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Get Full Access to University Physics - 13 Edition - Chapter 24 - Problem 16e
Get Full Access to University Physics - 13 Edition - Chapter 24 - Problem 16e

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For the system of capacitors shown in Fig. E24.16, find

ISBN: 9780321675460 31

Solution for problem 16E Chapter 24

University Physics | 13th Edition

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Problem 16E

For the system of capacitors shown in ?Fig. E24.16?, find the equivalent capacitance (a) between and c, and (b) between a and c.

Step-by-Step Solution:
Step 1 of 3

Solution 16E If two capacitors with capacitances C and C ar1 connecte2 in parallel, then the equivalent capacitance is given by C eq = C +1C …..(2) If two capacitors with capacitances C and C are1connected2in series, then the C C equivalent capacitance is given by C eq = C + C2 …..(2) 1 2 (a) Between b and c, the capacitors with capacitances 9.0 pF and 11.0 pF are parallel. Hence, their equivalent capacitance would be C eq = 9.0 pF + 11.0 pF = 20.0 pF So, 20.0 pF is the equivalent capacitance between b and c. (b) Between the points a and c, the capacitor with the 15 pF capacitance will now be in series with the C eq(calculated in part a). This equivalent capacitance can be calculated as shown below. C eq1= 15×20pF = 8.6 pF 15+20 Therefore, 8.6 pF is the equivalent capacitance between a and c.

Step 2 of 3

Step 3 of 3

ISBN: 9780321675460

This full solution covers the following key subjects: capacitance, Capacitors, equivalent, fig, Find. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. Since the solution to 16E from 24 chapter was answered, more than 287 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 16E from chapter: 24 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. The answer to “For the system of capacitors shown in ?Fig. E24.16?, find the equivalent capacitance (a) between and c, and (b) between a and c.” is broken down into a number of easy to follow steps, and 23 words.

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