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An air capacitor is made from two flat parallel plates

Chapter 24, Problem 26E

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QUESTION:

An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnitude of charge on each plate is 0.0180 µC when the potential difference is 200 V. (a) What is the capacitance? (b) What is the area of each plate? (c) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric-field strength of 3.0 X 106 V/m.) (d) When the charge is 0.0180 µC, what total energy is stored?

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QUESTION:

An air capacitor is made from two flat parallel plates 1.50 mm apart. The magnitude of charge on each plate is 0.0180 µC when the potential difference is 200 V. (a) What is the capacitance? (b) What is the area of each plate? (c) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric-field strength of 3.0 X 106 V/m.) (d) When the charge is 0.0180 µC, what total energy is stored?

ANSWER:

Solution 26E Step 1: Electric field is the negative gradient of the potential difference. E=(V/d) The charge in a parallel plate capacitor Q=CV

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