Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E = 3.20 X 105 V/m. When the space is filled with dielectric, the electric field is E = 2.50 X 105 V/m. (a) What is the charge density on each surface of the dielectric? (b) What is the dielectric constant?
Solution 37E Step 1 of 4: Given data, Electric field without dielectric, E = 3.2 × 10 V /m 0 5 Electric field dielectric, E = 2.5 × 10 V /m 12 2 2 Permittivity of free space, 0 8.854 × 10 C /N.m To find, (a) he charge density on each surface of the dielectric, = i (b) he dielectric constant, k=