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In Fig. P24.59, each capacitance C1 is 6.9 µF, and each

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 63P Chapter 24

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 63P

In Fig. P24.59, each capacitance C1 is 6.9 µF, and each capacitance C2 is 4.6 µF. (a) Compute the equivalent capacitance of the network between points a and b . (b) Compute the charge on each of the three capacitors nearest a and b when Vab = 420 V. (c) With 420 V across a and b, compute vcd.

Step-by-Step Solution:

Solution 63P Step 1 : Introduction : Here, we need to find the equivalent capacitance between a and b In the second part, we need to find charge on each of the three capacitors nearest to a and b and c and d Data given C1= 6.9 F C1= 4.6 F V = 420 V ab Considering the given figure

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Chapter 24, Problem 63P is Solved
Step 3 of 5

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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In Fig. P24.59, each capacitance C1 is 6.9 µF, and each