Solution Found!

As usual, the acceleration due to gravity in

Chapter 16, Problem 33

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

Problem 33PE

As usual, the acceleration due to gravity in these problems is taken to be g = 9.80 m / s2 , unless otherwise specified.

Suppose the length of a clock’s pendulum is changed by 1.000%, exactly at noon one day. What time will it read 24.00 hours later, assuming it the pendulum has kept perfect time before the change? Note that there are two answers, and perform the calculation to four-digit precision.

Questions & Answers

QUESTION:

Problem 33PE

As usual, the acceleration due to gravity in these problems is taken to be g = 9.80 m / s2 , unless otherwise specified.

Suppose the length of a clock’s pendulum is changed by 1.000%, exactly at noon one day. What time will it read 24.00 hours later, assuming it the pendulum has kept perfect time before the change? Note that there are two answers, and perform the calculation to four-digit precision.

ANSWER:

Solution

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back