Solve u t = k 2 u x 2 for 0 < x < L,t > 0, u(0,t) = T, u(L,t) = 0 for t 0, u(x, 0) = x(L x) for 0 x L.

Overview week of 9/12/16 3.3 Rules of Differentiation Power of X: d n (n1) Power Rule: / Xdx= nX Quotient Rule: / f(x)/g(x) = [(f(x) * g(x)) – (f(x) * g(x))] / [g(x)] 2 dx Product Rule: / [dxx) * g(x)] = [f(x) * g’(x)] + [g(x) * f’(x)] Chain Rule: / [dxg(x))] = [f(g(x))]’ * g’(x) Constant Multiple: Power rule d /dx(cf(x)) = c * f ’(x) 3.4...