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In Example 2 the decay constant for isotope RA1 was

Fundamentals of Differential Equations | 8th Edition | ISBN: 9780321747730 | Authors: R. Kent Nagle, Edward B. Saff, Arthur David Snider ISBN: 9780321747730 43

Solution for problem 24E Chapter 2.3

Fundamentals of Differential Equations | 8th Edition

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Fundamentals of Differential Equations | 8th Edition | ISBN: 9780321747730 | Authors: R. Kent Nagle, Edward B. Saff, Arthur David Snider

Fundamentals of Differential Equations | 8th Edition

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Problem 24E

Problem 24E

In Example 2 the decay constant for isotope RA1 was 10/sec, which expresses itself in the exponent of the rate term 50e-10t kg/sec. When the decay constant for RA2 is k = 2/sec, we see that in formula (14) for y the term (185/4)e-2t eventually dominates (has greater magnitude for t large).

(a) Redo Example 2 taking k = 20/sec. Now which term in the solution eventually dominates?

(b) Redo Example 2 taking k = 10/sec.

Step-by-Step Solution:

Solution:

Step 1:

Accept that the rate at which RA1 decays into RA2 is 50e-10t kg/sec. Since the rate of rot of  RA2 is relative to the mass y(t) of  RA2 introduce, the rate of progress of  RA2 is

50e-10t - ky ……..(i)

Where k > 0 is the decay steady.

Step 2 of 7

Chapter 2.3, Problem 24E is Solved
Step 3 of 7

Textbook: Fundamentals of Differential Equations
Edition: 8
Author: R. Kent Nagle, Edward B. Saff, Arthur David Snider
ISBN: 9780321747730

Since the solution to 24E from 2.3 chapter was answered, more than 986 students have viewed the full step-by-step answer. Fundamentals of Differential Equations was written by and is associated to the ISBN: 9780321747730. The full step-by-step solution to problem: 24E from chapter: 2.3 was answered by , our top Calculus solution expert on 07/11/17, 04:37AM. This full solution covers the following key subjects: SEC, Example, term, edo, dominates. This expansive textbook survival guide covers 67 chapters, and 2118 solutions. This textbook survival guide was created for the textbook: Fundamentals of Differential Equations , edition: 8. The answer to “In Example 2 the decay constant for isotope RA1 was 10/sec, which expresses itself in the exponent of the rate term 50e-10t kg/sec. When the decay constant for RA2 is k = 2/sec, we see that in formula (14) for y the term (185/4)e-2t eventually dominates (has greater magnitude for t large).(a) Redo Example 2 taking k = 20/sec. Now which term in the solution eventually dominates?(b) Redo Example 2 taking k = 10/sec.” is broken down into a number of easy to follow steps, and 74 words.

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In Example 2 the decay constant for isotope RA1 was