Variation of Parameters. Here is another procedure for

Chapter 2, Problem 36E

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QUESTION:

Variation of Parameters. Here is another procedure for solving linear equations that is particularly useful for higher-order linear equations. This method is called variation of parameters. It is based on the idea that just by knowing the form of the solution,we can substitute into the given equation and solvefor any unknowns. Here we illustrate the method forfirst-order equations (see Sections 4.6 and 6.4 for thegeneralization to higher-order equations).(a) Show that the general solution to has the form Where yh is a solution to equation (20) when Q (x) =0, C is a constant, and yp (x) = v (x) yh (x) for a suitable function v (x). [Hint: Show that we can take th = µ-1 (x) and then use equation (8).] We can in fact determine the unknown function yh by solving a separable equation. Then direct substitution of yyh in the original equation will give a simple equation that can be solved for y. Use this procedure to find the general solution to by completing the following steps:(b) Find a nontrivial solution yh to the separable equation (c) Assuming (21) has a solution of the form substitute this into equation(21), and simplify to obtain (d) Now integrate to get v (x) .(e) Verify that y(x) = cyh(x) + v (x)yh (x) is a general solution to (21).

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QUESTION:

Variation of Parameters. Here is another procedure for solving linear equations that is particularly useful for higher-order linear equations. This method is called variation of parameters. It is based on the idea that just by knowing the form of the solution,we can substitute into the given equation and solvefor any unknowns. Here we illustrate the method forfirst-order equations (see Sections 4.6 and 6.4 for thegeneralization to higher-order equations).(a) Show that the general solution to has the form Where yh is a solution to equation (20) when Q (x) =0, C is a constant, and yp (x) = v (x) yh (x) for a suitable function v (x). [Hint: Show that we can take th = µ-1 (x) and then use equation (8).] We can in fact determine the unknown function yh by solving a separable equation. Then direct substitution of yyh in the original equation will give a simple equation that can be solved for y. Use this procedure to find the general solution to by completing the following steps:(b) Find a nontrivial solution yh to the separable equation (c) Assuming (21) has a solution of the form substitute this into equation(21), and simplify to obtain (d) Now integrate to get v (x) .(e) Verify that y(x) = cyh(x) + v (x)yh (x) is a general solution to (21).

ANSWER:

Solution:Step-1:a)In this problem we need to show that the general solution of the differential equation has the form Given:.Consider, and .differentiate both sides with respect to x we get., since . , since . Therefore,. = 0.Therefore,.Clearly, is a solution of the differential equation .Step-2:multiplying both sides with we get.Integrating on both sides we get. , where , where Therefore, Step-3:b)In this problem we need to find a nontrivial solution to the sepa

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