Problem 95
The hybridization scheme for Xe in is (a) (b) (c) (d)
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Electrochemistry Redox reaction- Many biological processes ↳Reduction and Oxidation- Movement of electron from one species to another + A → A Oxidation: Loss of election A reduced B, A is the reducing Reduction: Gain of electron agent. B oxidized A B → B- Oxidation Is Loss Reduction Is Gain--OILRIG to remember + 2+ Zn(s) +2 H (aq)→Zn (aq) + H (g) 2 Zinc loses e Hydrogen gained e Oxidized. Reducing agent Reduced, Oxidizing agent H + F →2HF Molecular 2 2 ↳Need oxidation numbers. Oxidat
Step 2 of 3
Chapter 11, Problem 95 is Solved
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