Use the method discussed under “Equations with Linear Coefficients” to solve Problems 29–32.

Solution:Step 1</p>

In this problem we need to find the solution of the given differential equation.

Step 2</p>

Given :

Since the given equation is of the form such that therefore we assume and such that

and .

For we have (1)

For we have (2)

Solving (1) and (2), we get

From (1) we have . Putting in equation (2), we get

Putting in , we get

Since and therefore and .

Step 3</p>

Differentiating and , we get

and .

Substituting and in

, we get

Letting , we get