Solution Found!
Show that equation (13) reduces to an equation of the form
Chapter 2, Problem 44E(choose chapter or problem)
Show that equation (13) reduces to an equation of the form
\(\frac{d y}{d x}=G(a x+b y) \),
when \(a_{1} b_{2}=a_{2} b_{1}\). [Hint: If \(a_{1} b_{2}=a_{2} b_{1}\), then \(a_{2} / a_{1}=b_{2} / b_{1}=k\), so that \(a_{2}=k a_{1}\) and \(b_{2}=k b_{1}\).]
Equation Transcription:
Text Transcription:
{dy}over{dx}=G(ax+by)
a_{1}b_{2}=a_{2}b_{1}
a_{1}b_{2}=a_{2}b_{1}
a_{2}/a_{1}=b_{2}/b_{1}=k
a_{2}=ka_{1}
b_{2}=kb_{1}
Questions & Answers
QUESTION:
Show that equation (13) reduces to an equation of the form
\(\frac{d y}{d x}=G(a x+b y) \),
when \(a_{1} b_{2}=a_{2} b_{1}\). [Hint: If \(a_{1} b_{2}=a_{2} b_{1}\), then \(a_{2} / a_{1}=b_{2} / b_{1}=k\), so that \(a_{2}=k a_{1}\) and \(b_{2}=k b_{1}\).]
Equation Transcription:
Text Transcription:
{dy}over{dx}=G(ax+by)
a_{1}b_{2}=a_{2}b_{1}
a_{1}b_{2}=a_{2}b_{1}
a_{2}/a_{1}=b_{2}/b_{1}=k
a_{2}=ka_{1}
b_{2}=kb_{1}
ANSWER:
Solution
Step 1:
We have to show that given equation (13) reduces to the equation of the form
When