In Example 16-7, rather than use the quadratic formula to
Chapter 16, Problem 101(choose chapter or problem)
In Example 16-7, rather than use the quadratic formula to solve the quadratic equation, we could have proceeded in the following way. Substitute the value yielded by our failed assumption into the denominator of the quadratic equation; that is, use as the value of and solve for a new value of x. Use this second value of x to re-evaluate Solve the simple quadratic equation for a third value of x, and so on. After three or four trials, you will find that the value of x no longer changes. This is 3CH3NH24 = 10.00250 - second value of x2. 3CH3NH24: 3CH3NH24 10.00250 - 0.00102 x = 0.0010 the answer you are seeking. (a) Complete the calculation of the pH of 0.00250 M by this method, and show that the result is the same as that obtained by using the quadratic formula. (b) Use this method to determine the pH of 0.500 M
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