Consider the following: Li(s) 1 1 2 I2(g) n LiI(s) DH 5

Chapter 13, Problem 13.44

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Consider the following: \(\operatorname{Li}(s)+\frac{1}{2} \mathbf{I}_{2}(g) \rightarrow \operatorname{LiI}(s) \Delta H=-292 \mathrm{~kJ}\). Lil(s) has a lattice energy of \(-753 \mathrm{~kJ} / \mathrm{mol}\). The ionization energy of Li(g) is 520. kJ/mol, the bond energy of \(\mathbf{I}_{2}(g)\) is 151 kJ/mol, and the electron affinity of I(g) is \(-295 \mathrm{~kJ} / \mathrm{mol}\). Use these data to determine the heat of sublimation of Li(s).

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