CoCl4 22 forms a tetrahedral complex ion and Co(CN)6 32
Chapter 19, Problem 19.73(choose chapter or problem)
CoCl4 22 forms a tetrahedral complex ion and Co(CN)6 32 forms an octahedral complex ion. What is wrong about the following statements concerning each complex ion and the d orbital splitting diagrams? a. CoCl4 22 is an example of a strong-field case having two unpaired electrons. b. Because CN2 is a weak-field ligand, Co(CN)6 32 will be a low-spin case having four unpaired electrons.
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