Problem 1PE

(a) What is the resistance of ten 275-Ω resistors connected in series? (b) In parallel?

Solution 1PE

a)

The equivalent resistance in series combination is,

Rs = R1+ R2 + R3 +....+ Rn

= nR

= (10)(275Ω )

= 2750Ω

b)

he equivalent resistance in parallel combination is

1/Rp = 1 / R1 + 1 / R2 + 1 / R3 + ,,,,,+ 1 / R3n

1/Rp = 10/ 275Ω

= 275Ω / 10

=27.5 Ω

the equivalent resistance in parallel combination is 27.5 Ω