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The hot resistance of a flashlight bulb is 2.30 ? , and it

Chapter 21, Problem 21

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QUESTION:

The hot resistance of a flashlight bulb is \(2.30 \Omega\) , and it is run by a \(1.58-V\) alkaline cell having a \(0.100-\Omega\) internal resistance.

(a) What current flows?

(b) Calculate the power supplied to the bulb using \(I^{2} R_{\text {bulb }}\).

(c) Is this power the same as calculated using \(\frac{V^{2}}{R_{\text {bulb }}}\)?

Equation Transcription:

Text Transcription:

2.30 Omega

1.58-V

0.100-Omega

I^2R_bulb

V^2 / R_bulb

Questions & Answers

QUESTION:

The hot resistance of a flashlight bulb is \(2.30 \Omega\) , and it is run by a \(1.58-V\) alkaline cell having a \(0.100-\Omega\) internal resistance.

(a) What current flows?

(b) Calculate the power supplied to the bulb using \(I^{2} R_{\text {bulb }}\).

(c) Is this power the same as calculated using \(\frac{V^{2}}{R_{\text {bulb }}}\)?

Equation Transcription:

Text Transcription:

2.30 Omega

1.58-V

0.100-Omega

I^2R_bulb

V^2 / R_bulb

ANSWER:

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