Problem 23CQ

Apply the loop rule to loops abgefa and cbgedc in Figure 21.47.

Solution 23CQ

a) equation for loop abgefa is (35.5)I1 + (6..25 = 21 V

b) equation for loop cbgedc is ( 9.25I2 - ( 6.25I3 = +15 V

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College Physics - 1 Edition - Chapter 21 - Problem 23cq

ISBN: 9781938168000
42

College Physics | 1st Edition

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Problem 23CQ

Problem 23CQ

Apply the loop rule to loops abgefa and cbgedc in Figure 21.47.

Step-by-Step Solution:
##### Textbook: College Physics

##### Edition: 1

##### Author: Paul Peter Urone, Roger Hinrichs

##### ISBN: 9781938168000

Step 1 of 3

Solution 23CQ

a) equation for loop abgefa is (35.5)I1 + (6..25 = 21 V

b) equation for loop cbgedc is ( 9.25I2 - ( 6.25I3 = +15 V

Step 2 of 3
###### Chapter 21, Problem 23CQ is Solved

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Step 3 of 3

This full solution covers the following key subjects: abgefa, apply, cbgedc, figure, Loop. This expansive textbook survival guide covers 34 chapters, and 3125 solutions. The full step-by-step solution to problem: 23CQ from chapter: 21 was answered by , our top Physics solution expert on 07/07/17, 04:39PM. This textbook survival guide was created for the textbook: College Physics , edition: 1. The answer to “Apply the loop rule to loops abgefa and cbgedc in Figure 21.47.” is broken down into a number of easy to follow steps, and 12 words. Since the solution to 23CQ from 21 chapter was answered, more than 385 students have viewed the full step-by-step answer. College Physics was written by and is associated to the ISBN: 9781938168000.

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Apply the loop rule to loops abgefa and cbgedc in Figure