Find the currents flowing in the circuit in Figure \(21.52\). Explicitly show how you follow the steps in the Problem-Solving Strategies for Series and Parallel Resistors.
Figure \(21.52\)
Equation Transcription:
Text Transcription:
21.52
Solution 38PE
Apply the formula of node at point a,
I3 =I1 + I2
I1 + I2 -I3 = 0…… (1)
Apply the loop rule in loop aklefghija as follows,
40.5 I2 + 78.25 I3 = 18…… (2)
Apply the loop rule in loop abcdelka as follows,
25.1 I1 + 50.1 I2 = 24…… (3)
Now, substitute the value of I3 from equation (1) into equation (2), we get
25.1 I1 + 78.25 ( I1 + I2 ) = 18
25.1 I1 + 78.25 I1 + 78.25 I2 = 18
103.35I1 + 78.25I2 = 18…… (4)
Now, simplify the equation (4) and equation (3) and by solving the equations the value of currents is, I1 = 0.54A, I2 = -0.2057A and .I3 = 0.3365A
the current flowing in the circuit is I1 = 0.54A, I2 = -0.2057A and I3 = 0.3365A