Solution Found!
a. A roll of aluminum foil claims to be 50 sq ft or 4.65
Chapter 4, Problem 4.4.5(choose chapter or problem)
a. A roll of aluminum foil claims to be 50 sq ft or \(4.65 \mathrm{\ m}^{2}\). Show the conversion factors that would verify that these two measurements are equivalent.
b. One \(\mathrm{cm}^{3}\) of aluminum weighs 2.7 grams. If a sheet of aluminum foil is 0.003 8 cm thick, find the weight of the roll of aluminum foil in grams.
Questions & Answers
QUESTION:
a. A roll of aluminum foil claims to be 50 sq ft or \(4.65 \mathrm{\ m}^{2}\). Show the conversion factors that would verify that these two measurements are equivalent.
b. One \(\mathrm{cm}^{3}\) of aluminum weighs 2.7 grams. If a sheet of aluminum foil is 0.003 8 cm thick, find the weight of the roll of aluminum foil in grams.
ANSWER:Step 1 of 3
(a)
In general
\(\begin{aligned}1\mathrm{ft}&\approx0.305\mathrm{\ m}\\ 1\mathrm{ft}^2&\approx0.093\mathrm{\ m}^2\end{aligned}\)
The equation can be written in two ways:
\(1\approx\frac{0.093\mathrm{\ m}^2}{1\mathrm{ft}^2}\text{ and }1=\frac{1\mathrm{ft}^2}{0.093\mathrm{\ m}^2}\)