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In the August 1992 space shuttle flight, only 250 m of the

College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs ISBN: 9781938168000 42

Solution for problem 22PE Chapter 23

College Physics | 1st Edition

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College Physics | 1st Edition | ISBN: 9781938168000 | Authors: Paul Peter Urone, Roger Hinrichs

College Physics | 1st Edition

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Problem 22PE

In the August \(1992\) space shuttle flight, only \(250 m\) of the conducting tether considered in Example \(23.2\) could be let out. A \(40.0 V\) motional emf was generated in the Earth’s \(5.00 \times 10^{-5} \mathrm{~T}\) field, while moving at \(7.80 \times 10^{3} \mathrm{~m} / \mathrm{s}\) . What was the angle between the shuttle’s velocity and the Earth’s field, assuming the conductor was perpendicular to the field?

Equation Transcription:

Text Transcription:

1992

250 m

23.2

40.0 V

5.00 times 10^-5 T

7.80 times 10^3 m/s

Step-by-Step Solution:
Step 1 of 3

Solution 22PE

  =

 = 24.2o

The angle between the velocity and the space shuttle is 24.2o

Step 2 of 3

Chapter 23, Problem 22PE is Solved
Step 3 of 3

Textbook: College Physics
Edition: 1
Author: Paul Peter Urone, Roger Hinrichs
ISBN: 9781938168000

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In the August 1992 space shuttle flight, only 250 m of the