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In the August 1992 space shuttle flight, only 250 m of the
Chapter 23, Problem 22(choose chapter or problem)
In the August \(1992\) space shuttle flight, only \(250 m\) of the conducting tether considered in Example \(23.2\) could be let out. A \(40.0 V\) motional emf was generated in the Earth’s \(5.00 \times 10^{-5} \mathrm{~T}\) field, while moving at \(7.80 \times 10^{3} \mathrm{~m} / \mathrm{s}\) . What was the angle between the shuttle’s velocity and the Earth’s field, assuming the conductor was perpendicular to the field?
Equation Transcription:
Text Transcription:
1992
250 m
23.2
40.0 V
5.00 times 10^-5 T
7.80 times 10^3 m/s
Questions & Answers
QUESTION:
In the August \(1992\) space shuttle flight, only \(250 m\) of the conducting tether considered in Example \(23.2\) could be let out. A \(40.0 V\) motional emf was generated in the Earth’s \(5.00 \times 10^{-5} \mathrm{~T}\) field, while moving at \(7.80 \times 10^{3} \mathrm{~m} / \mathrm{s}\) . What was the angle between the shuttle’s velocity and the Earth’s field, assuming the conductor was perpendicular to the field?
Equation Transcription:
Text Transcription:
1992
250 m
23.2
40.0 V
5.00 times 10^-5 T
7.80 times 10^3 m/s
ANSWER:
Solution 22PE