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Get Full Access to College Physics - 1 Edition - Chapter 23 - Problem 22pe
Get Full Access to College Physics - 1 Edition - Chapter 23 - Problem 22pe

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# In the August 1992 space shuttle flight, only 250 m of the

ISBN: 9781938168000 42

## Solution for problem 22PE Chapter 23

College Physics | 1st Edition

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Problem 22PE

In the August $$1992$$ space shuttle flight, only $$250 m$$ of the conducting tether considered in Example $$23.2$$ could be let out. A $$40.0 V$$ motional emf was generated in the Earth’s $$5.00 \times 10^{-5} \mathrm{~T}$$ field, while moving at $$7.80 \times 10^{3} \mathrm{~m} / \mathrm{s}$$ . What was the angle between the shuttle’s velocity and the Earth’s field, assuming the conductor was perpendicular to the field?

Equation Transcription:

Text Transcription:

1992

250 m

23.2

40.0 V

5.00 times 10^-5 T

7.80 times 10^3 m/s

Step-by-Step Solution:
Step 1 of 3

Solution 22PE

=

= 24.2o

The angle between the velocity and the space shuttle is 24.2o

Step 2 of 3

Step 3 of 3

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