In general, for straight motion of a vehicle with constant

Chapter 8, Problem 8.6.35

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In general, for straight motion of a vehicle with constant acceleration, a, the velocity, v, at any time, t, is the original velocity, v0, plus acceleration multiplied by time: v v0 at. The distance traveled in time t is . a. A criminal going at speed vc passes a police car and immediately accelerates with constant acceleration ac. If the police car has constant acceleration ap ac, starting from 0 mph, how long will it take to pass the criminal? Give t in terms of vc, ap, and ac. b. At what time are the police and the criminal traveling at the same speed? If they are traveling at the same speed, does it mean the police have caught up with the criminal? Explain.