In Problems 17 and 18, use the results of Problem 42 in Exercises 9.5 to find a general solution to the given Cauchy–Euler system for t > 0.

CEM 141 Lecture 30: Molecular Shape and Polarity Dr. Jian Hu November 14 , 2016 For NH 4 the electron center geometry is the same as its molecular geometry because it does not have lone electron pairs CO 2as a linear electron center geometry, so the carbon has sp hybridization H2O has a bent molecular shape because it has 2 lone pairs of electrons...