Solution Found!
In 13 and 14 the given two-parameter family is a solution
Chapter 4, Problem 13E(choose chapter or problem)
In Problems 13 and 14 the given two-parameter family is a solution of the indicated differential equation on the interval \((-\infty,)\). Determine whether a member of the family can be found that satisfies the boundary conditions
\(y=c_{1} e^{x} \cos x+c_{2} e^{x} \sin x ; \quad y^{\prime \prime}-2 y^{\prime}+2 y=0\)
(a) \(y(0)=1, \quad y^{\prime}(\pi)=0\)
(b) \(y(0)=1, \quad y(\pi)=-1\)
(c) \(y(0)=1, \quad y(\pi / 2)=1\)
(d) \(y(0)=0, \quad y(\pi)=0\).
Text Transcription:
-infty
y=c_{1} e^{x} \cos x+c_{2} e^{x} \sin x ; \quad y^{\prime \prime}-2 y^{\prime}+2 y=0
y(0) = 1, y(p) = 0
y(0) = 1, y(p) = 1
y(0) = 1, y(p2) = 1
y(0) = 0, y(p) = 0
Questions & Answers
QUESTION:
In Problems 13 and 14 the given two-parameter family is a solution of the indicated differential equation on the interval \((-\infty,)\). Determine whether a member of the family can be found that satisfies the boundary conditions
\(y=c_{1} e^{x} \cos x+c_{2} e^{x} \sin x ; \quad y^{\prime \prime}-2 y^{\prime}+2 y=0\)
(a) \(y(0)=1, \quad y^{\prime}(\pi)=0\)
(b) \(y(0)=1, \quad y(\pi)=-1\)
(c) \(y(0)=1, \quad y(\pi / 2)=1\)
(d) \(y(0)=0, \quad y(\pi)=0\).
Text Transcription:
-infty
y=c_{1} e^{x} \cos x+c_{2} e^{x} \sin x ; \quad y^{\prime \prime}-2 y^{\prime}+2 y=0
y(0) = 1, y(p) = 0
y(0) = 1, y(p) = 1
y(0) = 1, y(p2) = 1
y(0) = 0, y(p) = 0
ANSWER:Step 1 of 9
In this problem we need to determine whether a member of the family can be found that satisfies the boundary conditions.