Solution Found!
The roots of a cubic auxiliary equation are m1 = 4 and m2=
Chapter 4, Problem 59E(choose chapter or problem)
Two roots of a cubic auxiliary equation with real coefficients are \(m_{1}=-\frac{1}{2} \text { and } m_{2}=3+i\) and What is the corresponding homogeneous linear differential equation? Discuss: Is your answer unique?
Text Transcription:
m_{1}=-\frac{1}{2} \text { and } m_{2}=3+i
Questions & Answers
QUESTION:
Two roots of a cubic auxiliary equation with real coefficients are \(m_{1}=-\frac{1}{2} \text { and } m_{2}=3+i\) and What is the corresponding homogeneous linear differential equation? Discuss: Is your answer unique?
Text Transcription:
m_{1}=-\frac{1}{2} \text { and } m_{2}=3+i
ANSWER:Step 1 of 3
We know that if an equation has a complex root, then it also has another complex conjugate root. Hence, the cubic auxiliary equation has three roots, and .